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1.2. Equations (2/15) -- Mathematics for Public and Occupational ...

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1.2. Equations

1.2. Equations Equations Equation: a mathematical sentence that contains two expressions and is separated by an equal sign (both sides of the equation have the same value). To solve an equation we find a particular value for the variable in the equation that makes the equation true (left side = right side). Example: For the equation x + 4 = 5 only x = 1 can make it true, since 1 + 4 = 5 (Left side = Right side) Solution of an equation: the value of the variable in the equation that makes the equation true. Example 1.2.1 Indicate whether each of the given number is a solution to the given equation. | 1) 2 : 4x – 3 = 5 | 4 ∙ 2 – 3 5 | 5 5 | Yes | Replace x with 2. | | 2) 15 : y = -3 | -3 | -3 -3 | Yes | Replace y with 15. | | 3) : 8t = 3 | 8 () 3 | 4 ≠ 3 | No | Cannot replace t with . | Solving Equations Basic rules for solving one-step equations: - Add, subtract, multiply or divide the same quantity to both sides of an equation to obtain a valid equation. - Remember to always do the same thing to both sides of the equation (balance). Properties for solving equations: | Properties | Equality | Example | | Addition property of equality | A = B A + C = B + C | Solve x = 9 | | Subtraction property of equality | A = B A – C = B – C | Solve y = -13 | | Multiplication property of equality | A = B A · C = B · C | Solve m = 18 | | Division property of equality | A = B (C ≠ 0) | Solve n = –5 | Example 1.2.2 Solve the following equations. | 1) | Property of addition. | | | Check: | Replace x with 14. | | 2) | Property of subtraction. | | | 3) | Property of multiplication. | | | 4) | Property of division. | | Multi-step equation: an equation that requires more than one step to solve it. Procedure for solving multi-step equations: | | Steps | Example | | Solve | || | Multiply each term by 5. | | | || | || | Subtract 10 from both sides. Subtract 6y from both sides. | | | Divide both sides by -5. | | | Replace y with 2. Multiply each term by 5. LS = RS (correct) | Equations involving decimals: Multiply every term of both sides of the equation by a multiple of 10 (10, 100, 1000, etc.) to clear the decimals (based on the number with the largest number of decimal places in the equation). | Steps | Example | | Solve | || | The largest number of decimal place is two. | | | Add 12 to both sides. Add 426x to both sides. | | | Example 1.2.3 | Solve 0.4y + 0.08 = 0.016 | The largest number of decimal place is three. | | 1000(0.4y) + 1000(0.08) = 1000(0.016) | Multiply each term by 1000. | | 400y + 80 = 16 | Combine like terms. | | 400y = -64 | Divide both sides by 400. | | y = – 0.16 | Equations involving fractions: | Steps | Example | | Solve | || | | | | Add 6t to both sides. Subtract 9 from both sides. | | | Divide both sides by 10. | Word Problems Identifying keywords: - When trying to figure out the correct operation ( + , – , × , ÷ , etc.) in a word problem it is important to pay attention to keywords (clues to what the problem is asking). - Identifying keywords an
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