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68 Angular Acceleration (45/58) -- Physics

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68 Angular Acceleration

68 Angular Acceleration Learning Objectives By the end of this section, you will be able to: - Describe uniform circular motion. - Explain non-uniform circular motion. - Calculate angular acceleration of an object. - Observe the link between linear and angular acceleration. where θ is the angle of rotation as seen in Figure 1. The relationship between angular velocity ω and linear velocity v was also defined in Rotation Angle and Angular Velocity as or [latex]\omega =\frac{v}{r}\\[/latex] where r is the radius of curvature, also seen in Figure 1. According to the sign convention, the counter clockwise direction is considered as positive direction and clockwise direction as negative Angular velocity is not constant when a skater pulls in her arms, when a child starts up a merry-go-round from rest, or when a computer’s hard disk slows to a halt when switched off. In all these cases, there is an angular acceleration, in which ω changes. The faster the change occurs, the greater the angular acceleration. Angular acceleration α is defined as the rate of change of angular velocity. In equation form, angular acceleration is expressed as follows: where Δω is the change in angular velocity and Δt is the change in time. The units of angular acceleration are (rad/s)/s, or rad/s2. If ω increases, then α is positive. If ω decreases, then α is negative. Example 1. Calculating the Angular Acceleration and Deceleration of a Bike Wheel Suppose a teenager puts her bicycle on its back and starts the rear wheel spinning from rest to a final angular velocity of 250 rpm in 5.00 s. (a) Calculate the angular acceleration in rad/s2. (b) If she now slams on the brakes, causing an angular acceleration of -87.3 rad/s2, how long does it take the wheel to stop? Strategy for (a) The angular acceleration can be found directly from its definition in [latex]\alpha =\frac{\Delta \omega }{\Delta t}\\[/latex] because the final angular velocity and time are given. We see that Δω is 250 rpm and Δt is 5.00 s. Solution for (a) Entering known information into the definition of angular acceleration, we get [latex]\begin{array}{lll}\alpha & =& \frac{\Delta \omega }{\Delta t}\\ & =& \frac{\text{250 rpm}}{\text{5.00 s}}\text{.}\end{array}\\[/latex] Because Δω is in revolutions per minute (rpm) and we want the standard units of rad/s2 for angular acceleration, we need to convert Δω from rpm to rad/s: [latex]\begin{array}{c}\Delta{\omega} &=& 250 \frac{\text{rev}}{\text{min}} \cdot \frac{2\pi\text{ rad}}{\text{rev}} \cdot \frac{1\text{ min}}{60\text{ sec}} \\ &=& 26.2 \frac{\text{rad}}{\text{s}}\end{array}\\[/latex] Entering this quantity into the expression for α, we get [latex]\begin{array}{lll}\alpha & =& \frac{\Delta \omega }{\Delta t}\\ & =& \frac{\text{26.2 rad/s}}{\text{5.00 s}}\\ & =& \text{5.24}{\text{ rad/s}}^{2}\text{.}\end{array}\\[/latex] Strategy for (b) In this part, we know the angular acceleration and the initial angular velocity. We can find the stoppage time by using the def
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