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88 Pressure (59/58) -- Physics

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88 Pressure

88 Pressure Learning Objectives By the end of this section, you will be able to: - Define pressure. - Explain the relationship between pressure and force. - Calculate force given pressure and area. where F is a force applied to an area A that is perpendicular to the force. Pressure Pressure is defined as the force divided by the area perpendicular to the force over which the force is applied, or [latex]P=\frac{F}{A}\\[/latex] A given force can have a significantly different effect depending on the area over which the force is exerted, as shown in Figure 1. The SI unit for pressure is the pascal, where [latex]1\text{ Pa}=1{\text{N/m}}^{2}\\[/latex]. In addition to the pascal, there are many other units for pressure that are in common use. In meteorology, atmospheric pressure is often described in units of millibar (mb), where [latex]\text{100 mb}=1\times {\text{10}}^{5}{\text{ Pa}}\\[/latex]. Pounds per square inch (lb/in2 or psi) is still sometimes used as a measure of tire pressure, and millimeters of mercury (mm Hg) is still often used in the measurement of blood pressure. Pressure is defined for all states of matter but is particularly important when discussing fluids. Example 1. What Force Does a Pressure Exert? An astronaut is working outside the International Space Station where the atmospheric pressure is essentially zero. The pressure gauge on her air tank reads 6.90 × 106 Pa. What force does the air inside the tank exert on the flat end of the cylindrical tank, a disk 0.150 m in diameter? Strategy We can find the force exerted from the definition of pressure given in [latex]P=\frac{F}{A}\\[/latex], provided we can find the area A acted upon. Solution By rearranging the definition of pressure to solve for force, we see that F = PA Here, the pressure P is given, as is the area of the end of the cylinder A, given by A = π r2. Thus, [latex]\begin{array}{lll}F& =& \left(6.90\times {\text{10}}^{6}{\text{N/m}}^{2}\right)\left(3.14\right){\left(0.0750 \text{ m}\right)}^{2}\\ & =& 1.22\times {\text{10}}^{5}\text{ N}\end{array}\\[/latex]. Discussion Wow! No wonder the tank must be strong. Since we found F = PA, we see that the force exerted by a pressure is directly proportional to the area acted upon as well as the pressure itself. The force exerted on the end of the tank is perpendicular to its inside surface. This direction is because the force is exerted by a static or stationary fluid. We have already seen that fluids cannot withstand shearing (sideways) forces; they cannot exert shearing forces, either. The forces due to pressure have well-defined directions: they are always exerted perpendicular to any surface. (See the tire in Figure 2, for example.) Finally, note that pressure is exerted on all surfaces. Swimmers, as well as the tire, feel pressure on all sides. (See Figure 3.) PhET Explorations: Gas Properties Section Summary - Pressure is the force per unit perpendicular area over which the force is applied. In equation form, pressure
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