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Chapter 14. Inductance (95/56) -- University Physics Volume 2

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Chapter 14. Inductance

Chapter 14. Inductance 14.3 Energy in a Magnetic Field Learning Objectives By the end of this section, you will be able to: - Explain how energy can be stored in a magnetic field - Derive the equation for energy stored in a coaxial cable given the magnetic energy density The energy of a capacitor is stored in the electric field between its plates. Similarly, an inductor has the capability to store energy, but in its magnetic field. This energy can be found by integrating the magnetic energy density, over the appropriate volume. To understand where this formula comes from, let’s consider the long, cylindrical solenoid of the previous section. Again using the infinite solenoid approximation, we can assume that the magnetic field is essentially constant and given by [latex]B={\mu }_{0}nI[/latex] everywhere inside the solenoid. Thus, the energy stored in a solenoid or the magnetic energy density times volume is equivalent to With the substitution of Equation 14.14, this becomes Although derived for a special case, this equation gives the energy stored in the magnetic field of any inductor. We can see this by considering an arbitrary inductor through which a changing current is passing. At any instant, the magnitude of the induced emf is [latex]\epsilon =Ldi\text{/}dt,[/latex] so the power absorbed by the inductor is The total energy stored in the magnetic field when the current increases from 0 to I in a time interval from 0 to t can be determined by integrating this expression: Example Self-Inductance of a Coaxial Cable Equation 14.11 shows two long, concentric cylindrical shells of radii [latex]{R}_{1}[/latex] and [latex]{R}_{2}.[/latex] As discussed in Capacitance on capacitance, this configuration is a simplified representation of a coaxial cable. The capacitance per unit length of the cable has already been calculated. Now (a) determine the magnetic energy stored per unit length of the coaxial cable and (b) use this result to find the self-inductance per unit length of the cable. Strategy The magnetic field both inside and outside the coaxial cable is determined by Ampère’s law. Based on this magnetic field, we can use Equation 14.22 to calculate the energy density of the magnetic field. The magnetic energy is calculated by an integral of the magnetic energy density times the differential volume over the cylindrical shell. After the integration is carried out, we have a closed-form solution for part (a). The self-inductance per unit length is determined based on this result and Equation 14.22. Solution Show Answer - We determine the magnetic field between the conductors by applying Ampère’s law to the dashed circular path shown in Figure 14.11(b). Because of the cylindrical symmetry, [latex]\stackrel{\to }{\textbf{B}}[/latex] is constant along the path, and [latex]\oint \stackrel{\to }{\textbf{B}}·d\stackrel{\to }{\textbf{l}}=B\left(2\pi r\right)={\mu }_{0}I.[/latex] This gives us [latex]B=\frac{{\mu }_{0}I}{2\pi r}.[/latex] In the region outsid
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