Private: Chapter Six
Determining Empirical and Molecular Formulas (6.2)
Determining Empirical and Molecular Formulas
The previous section discussed the relationship between the bulk mass of a substance and the number of atoms or molecules it contains (moles). Given the chemical formula of the substance, one may determine the amount of the substance (moles) from its mass, and vice versa. But what if the chemical formula of a substance is unknown? In this section, these same principles will be applied to derive the chemical formulas of unknown substances from experimental mass measurements.
Percent Composition
The elemental makeup of a compound defines its chemical identity, and chemical formulas are the most succinct way of representing this elemental makeup. When a compound’s formula is unknown, measuring the mass of each of its constituent elements is often the first step in the process of determining the formula experimentally. The results of these measurements permit the calculation of the compound’s percent composition, defined as the percentage by mass of each element in the compound. For example, consider a gaseous compound composed solely of carbon and hydrogen. The percent composition of this compound could be represented as follows:
% H = [latex]\frac{\text{mass H}}{\text{mass compound}}[/latex] x `100%
% C = [latex]\frac{\text{mass C}}{\text{mass compound}}[/latex] x 100%
If analysis of a 10.0-g sample of this gas showed it to contain 2.5 g H and 7.5 g C, the percent composition would be calculated to be 25% H and 75% C:
% H = [latex]\frac{2.5 \text{g H}}{10.0 \text{g compound}}[/latex] x `100% = 75%
% C = [latex]\frac{7.5 \text{g C}}{10.0 \text{g compound}}[/latex] x `100% = 75%
EXAMPLE 6.3
Calculation of Percent Composition
Analysis of a 12.04-g sample of a liquid compound composed of carbon, hydrogen, and nitrogen showed it to contain 7.34 g C, 1.85 g H, and 2.85 g N. What is the percent composition of this compound?
Solution
To calculate percent composition, divide the experimentally derived mass of each element by the overall mass of the compound, and then convert to a percentage:
% C = [latex]\frac{7.34 \text{g C}}{12.04 \text{g compound}}[/latex] x `100% = 61%
% H = [latex]\frac{1.85 \text{g H}}{12.04 \text{g compound}}[/latex] x `100% = 15.4%
% N = [latex]\frac{2.85 \text{g N}}{12.04 \text{g compound}}[/latex] x `100% = 23.7%
The analysis results indicate that the compound is 61.0% C, 15.4% H, and 23.7% N by mass.
Check Your Learning
A 24.81-g sample of a gaseous compound containing only carbon, oxygen, and chlorine is determined to contain 3.01 g C, 4.00 g O, and 17.81 g Cl. What is this compound’s percent composition?
ANSWER:
12.1% C, 16.1% O, 71.8% Cl
Determining Percent Composition from Molecular or Empirical Formulas
Percent composition is also useful for evaluating the relative abundance of a given element in different compounds of known formulas. As one example, consider the common nitrogen-containing fertilizers ammonia