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Introduction to Quantum Physics (84/66) -- College Physics 2

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Introduction to Quantum Physics

Introduction to Quantum Physics 98 Photon Energies and the Electromagnetic Spectrum Learning Objectives - Explain the relationship between the energy of a photon in joules or electron volts and its wavelength or frequency. - Calculate the number of photons per second emitted by a monochromatic source of specific wavelength and power. Ionizing Radiation A photon is a quantum of EM radiation. Its energy is given by [latex]E=\text{hf}[/latex] and is related to the frequency [latex]f[/latex] and wavelength [latex]\lambda[/latex] of the radiation by where [latex]E[/latex] is the energy of a single photon and [latex]c[/latex] is the speed of light. When working with small systems, energy in eV is often useful. Note that Planck’s constant in these units is Since many wavelengths are stated in nanometers (nm), it is also useful to know that These will make many calculations a little easier. All EM radiation is composed of photons. Figure 98.1 shows various divisions of the EM spectrum plotted against wavelength, frequency, and photon energy. Previously in this book, photon characteristics were alluded to in the discussion of some of the characteristics of UV, x rays, and [latex]\gamma[/latex] rays, the first of which start with frequencies just above violet in the visible spectrum. It was noted that these types of EM radiation have characteristics much different than visible light. We can now see that such properties arise because photon energy is larger at high frequencies. Photons act as individual quanta and interact with individual electrons, atoms, molecules, and so on. The energy a photon carries is, thus, crucial to the effects it has. Table 98.1 lists representative submicroscopic energies in eV. When we compare photon energies from the EM spectrum in Figure 98.1 with energies in the table, we can see how effects vary with the type of EM radiation. Gamma rays, a form of nuclear and cosmic EM radiation, can have the highest frequencies and, hence, the highest photon energies in the EM spectrum. For example, a [latex]\gamma[/latex]-ray photon with [latex]f{\text{= 10}}^{\text{21}}\phantom{\rule{0.25em}{0ex}}\text{Hz}[/latex] has an energy [latex]E=\text{hf}=6.63×{\text{10}}^{\text{–13}}\phantom{\rule{0.25em}{0ex}}\text{J}=4\text{.}\text{14 MeV.}[/latex] This is sufficient energy to ionize thousands of atoms and molecules, since only 10 to 1000 eV are needed per ionization. In fact, [latex]\gamma[/latex] rays are one type of ionizing radiation, as are x rays and UV, because they produce ionization in materials that absorb them. Because so much ionization can be produced, a single [latex]\gamma[/latex]-ray photon can cause significant damage to biological tissue, killing cells or damaging their ability to properly reproduce. When cell reproduction is disrupted, the result can be cancer, one of the known effects of exposure to ionizing radiation. Since cancer cells are rapidly reproducing, they are exceptionally sensitive to the disruption produced by
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