Chapter 8: Angular Kinetics
8.5 Simple Machines
Authors: Paul Peter Urone, Roger Hinrichs
Adapted by: Rob Pryce, Alix Blacklin
Learning Objectives
By the end of this section, you will be able to:
- Describe different simple machines.
- Calculate the mechanical advantage.
Simple machines are devices that can be used to multiply or augment a force that we apply – often at the expense of a distance through which we apply the force. The word for “machine” comes from the Greek word meaning “to help make things easier.” Levers, gears, pulleys, wedges, and screws are some examples of machines. Energy is still conserved for these devices because a machine cannot do more work than the energy put into it. However, machines can reduce the input force that is needed to perform the job. The ratio of output to input force magnitudes for any simple machine is called its mechanical advantage (MA).
One of the simplest machines is the lever, which is a rigid bar pivoted at a fixed place called the fulcrum. Torques are involved in levers, since there is rotation about a pivot point. Distances from the physical pivot of the lever are crucial, and we can obtain a useful expression for the MA in terms of these distances.
The figure above shows a lever type that is used as a nail puller. Crowbars, seesaws, and other such levers are all analogous to this one. [latex]{\mathbf{\text{F}}}_{\text{i}}[/latex] is the input force and [latex]{\mathbf{\text{F}}}_{\text{o}}[/latex] is the output force. There are three vertical forces acting on the nail puller (the system of interest) – these are [latex]{\mathbf{\text{F}}}_{\text{i}},\phantom{\rule{0.25em}{0ex}}{\mathbf{\text{F}}}_{\text{n}},[/latex] and [latex]\mathbf{\text{N}}[/latex]. [latex]{\mathbf{\text{F}}}_{\text{n}}[/latex] is the reaction force back on the system, equal and opposite to [latex]{\mathbf{\text{F}}}_{\text{o}}[/latex]. (Note that [latex]{\mathbf{\text{F}}}_{\text{o}}[/latex] is not a force on the system.) [latex]\mathbf{\text{N}}[/latex] is the normal force upon the lever, and its torque is zero since it is exerted at the pivot. The torques due to [latex]{\mathbf{\text{F}}}_{\text{i}}[/latex] and [latex]{\mathbf{\text{F}}}_{\text{n}}[/latex] must be equal to each other if the nail is not moving, to satisfy the second condition for equilibrium [latex]\left(\text{net}\phantom{\rule{0.25em}{0ex}}\tau =0\right)[/latex]. (In order for the nail to actually move, the torque due to [latex]{\mathbf{\text{F}}}_{\text{i}}[/latex] must be ever-so-slightly greater than torque due to [latex]{\mathbf{\text{F}}}_{\text{n}}[/latex].) Hence,
Notice that [latex]{\mathbf{\text{r}}}_{\text{i}}[/latex] is the distance from the pivot point to the point where the input force [latex]{\mathbf{\text{F}}}_{\text{i}}[/latex] is applied, and [latex]{\mathbf{\text{r}}}_{\text{o}}[/latex] (not labeled on the diagram) is the distance from the pivot point to the point where the output force [latex]{\mathbf{\text{F}}}_{\text{o}}[/latex] is ap