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Alex Rivera
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I need to get the first and last dimension of an numpy.ndarray of arbitrary size. If I have shape(A) = (3,4,4,4,4,4,4,3) my first Idea would be to do result = shape(A)[0,-1] but that doesn't seem to work with tuples, why not ?? Is there a neater way of doing this than s=shape(A) result=(s[0], s[-1]) Thanks for any help
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