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I'm re-asking this question in a simplified and expanded manner.
Consider these sql statements:
create table foo (id INT, score INT);
insert into foo values (106, 4);
insert into foo values (107, 3);
insert into foo values (106, 5);
insert into foo values (107, 5);
select T1.id, avg(T1.score) avg1
from foo T1
group by T1.id
having not exists (
select T2.id, avg(T2.score) avg2
from foo T2
group by T2.id
having avg2 > avg1);
Using sqlite, the select statement returns:
id avg1
---------- ----------
106 4.5
107 4.0
and mysql returns:
+------+--------+
| id | avg1 |
+------+--------+
| 106 | 4.5000 |
+------+--------+
As far as I can tell, mysql's results are correct, and sqlite's are incorrect. I tried to cast to real with sqlite as in the following but it returns two records still:
select T1.id, cast(avg(cast(T1.score as real)) as real) avg1
from foo T1
group by T1.id
having not exists (
select T2.id, cast(avg(cast(T2.score as real)) as real) avg2
from foo T2
group by T2.id
having avg2 > avg1);
Why does sqlite return two records?
Quick update:
I ran the statement against the latest sqlite version (3.7.11) and still get two records.
Another update:
I sent an email to sqlite-users@sqlite.org about the issue.
Myself, I've been playing with VDBE and found something interesting. I split the execution trace of each loop of not exists (one for each avg group).
To have three avg groups, I used the following statements:
create table foo (id VARCHAR(1), score INT);
insert into foo values ('c', 1.5)