I have a Java program running on a Linux computer, and want to find the process ID (pid) of its process. I know the ps command can provide this information, but its output is confusing because it has so much extraneous information. How can I get just the pid?

I am using MPJ library in java program for Pagerank algorithm. I compile it by

javac -cp .:$MPJ_HOME/lib/mpj.jar MpiPageRank.java

and run by

mpjrun.sh -np 2 MpiPageRank

where -np is number of process

Now i have to find its pid

ps -ef|grep java

like

mpjrun.sh -np 2 MpiPageRank & sleep 2
ps -ef | grep java

I get

pnewaska 27866 27837 99 21:28 pts/45   00:00:09 java -cp /u/pnewaska/mpj-v0_38/lib/smpdev.jar:/u/pnewaska/mpj-v0_38/lib/xdev.jar:/u/pnewaska/mpj-v0_38/lib/mpjbuf.jar:/u/pnewaska/mpj-v0_38/lib/loader2.jar:/u/pnewaska/mpj-v0_38/lib/starter.jar:/u/pnewaska/mpj-v0_38/lib/mpiExp.jar runtime.starter.MulticoreStarter /nfs/nfs1/home/pnewaska/DistributedSystems/Project3 10 smpdev useLocalLoader EMPTY MpiPageRank -i input.500k0 -n 10 -o

Now I want to extract MpiPageRank from only 1 linux comman to get its pid ie 27866. how do i do that ?

java linux pid ps
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