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Alex Rivera
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I'm really new with bash, but it's one of the subjects on school. One of the exercises was: Give the line number of the file "/etc/passwd" where the information about your own login is. Suppose USERNAME is my own login ID, I was able to do it perfectly in this way: cat /etc/passwd -n | grep USERNAME | cut -f1 Which simply gave the line number required (there may be a more optimised way). I wondered however, if there was a way to make the command more general so that it uses the output of whoami to represent the grep pattern, without scripting or using a variable . In other words, to keep it an easy-to-read one-line command, like so: cat /etc/passwd -n | grep (whoami) | cut -f1 Sorry if this is a really noob question.
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