I'm writing a brainfuck interpreter in Haskell, and I came up with what I believe to be a very interesting description of a program:

data Program m = Instruction (m ()) (Program m)
               | Control (m (Program m))
               | Halt

However, it's tricky to parse a textual representation of a brainfuck program into this data type. The problem arises with trying to correctly parse square brackets, because there is some knot-tying to do so that the final Instruction inside a loop links to the loop's Control again.

A bit more preliminary information. See this version on the github repo for all the details.

type TapeM = StateT Tape IO
type TapeP = Program TapeM
type TapeC = Cont TapeP

branch :: Monad m => m Bool -> Program m -> Program m -> Program m
branch cond trueBranch falseBranch =
  Control ((\b -> if b then trueBranch else falseBranch) `liftM` cond)

loopControl :: TapeP -> TapeP -> TapeP
loopControl = branch (not <$> is0)

Here's what I tried:

toProgram :: String -> TapeP
toProgram = (`runCont` id) . toProgramStep

liftI :: TapeM () -> String -> TapeC TapeP
liftI i cs = Instruction i <$> toProgramStep cs

toProgramStep :: String -> TapeC TapeP
toProgramStep ('>':cs) = liftI right cs
-- similarly for other instructions
toProgramStep ('[':cs) = push (toProgramStep cs)
toProgramStep (']':cs) = pop (toProgramStep cs)

push :: TapeC TapeP -> TapeC TapeP
push mcontinue = do
  continue <- mcontinue
  cont (\breakMake -> loopControl continue (breakMake continue))

pop :: TapeC TapeP -> TapeC TapeP
pop mbreak = do
  break <- mbreak
  cont (\continueMake -> loopControl (continueMake break) break)

I figured I could somehow use co

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