Delete vs operator delete (and void pointer)

Does delete ptr differ from operator delete(ptr) only in this, that delete calls ptr destructor? Or in other words, does delete ptr first call a destructor of ptr and then operator delete(ptr) to free allocated memory? Then is delete ptr technically equivalent to the following:

T * ptr = new T;

//delete ptr equivalent:
ptr->~T();
::operator delete(static_cast<void *>(ptr));

?