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I have to open a .exe file from my Java program. So I tried following code First. Process process = runtime.exec("c:\\program files\\test\\test.exe"); But I was getting some error. Then I found out that the exe has to be launched from that location that is c://program files/test/ only then it will open with out errors. So I decided to write a .bat file and execute so that it will cd to that location and execute the .exe file. Following is my code: BufferedWriter fileOut; String itsFileLocation = "c:\\program files\\test\\" System.out.println(itsFileLocation); try { fileOut = new BufferedWriter(new FileWriter("C:\\test.bat")); fileOut.write("cd\\"+"\n"); fileOut.write("cd "+ itsFileLocation +"\n"); fileOut.write("test.exe"+"\n"); fileOut.write("exit"+"\n"); fileOut.close(); // Close the output stream after all output is done. } catch (IOException e1) { e1.printStackTrace(); } // Create the Buffered Writer object to write to a file called filename.txt Runtime runtime = Runtime.getRuntime(); try { Process process =runtime.exec("cmd /c start C:\\test.bat"); } catch (IOException e) { e.printStackTrace(); } The above code works perfectly. However, the command prompt is also opened at the back of my .exe (Application). It closes only after the .exe file exits.. I need to clse my command prompt when my application stats. My .bat file will be like following after it is written by the program. cd\ cd C:\Program Files\test\ test.exe exit

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