23
You can always cast first:
Math.ceil((double)3/2)
In Java, 3/2 = 1 because it uses integer division. There's no function that can "fix" this afterwards. What you have to do is to force a float divison and round up the result:
int result = (int)Math.ceil( ((float)3) / ((float)2) );
Math.ceil will help, provided you use floating point numbers. The problem is that 3/2, in integer division, is 1. By the time the value gets to whatever function, be it Math.ceil or something else, the value is simply 1. Any trailing decimal portion is gone.
if (a % b == 0)
{
return (a / b);
}
else
{
return (a / b) + 1;
}
Exploits integer division to do what you want. I don't know of a math function that does this, but why not roll your own?