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Alex Rivera
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I add a ListView on runtime like this: MainMenue = getResources().getStringArray(R.array.Unit); // remove all controls LinearLayout formLayout = (LinearLayout)findViewById(R.id.submenue); formLayout.removeAllViews(); menueview = new ListView(getApplicationContext()); menueview.setVisibility(ListView.VISIBLE); LinearLayout.LayoutParams params = new LinearLayout.LayoutParams( LayoutParams.FILL_PARENT, LayoutParams.WRAP_CONTENT); params.gravity = Gravity.RIGHT; menueview.setLayoutParams(params); menueview.setAdapter(new submenueadapter(menueview.getContext(), MainMenue)); // Set the on Item SetMenueOnClick() ; formLayout.addView(menueview); and then I add a item click listener like this: public void SetMenueOnClick() { menueview.setOnItemClickListener(new OnItemClickListener() { public void onItemClick(AdapterView<?> parent, View view, int position, long id) { final String text = (String) ((TextView)view).getText(); } }); } But then I have an error: 06-03 10:59:25.862: E/AndroidRuntime(14732): at android.view.ViewRoot.handleMessage(ViewRoot.java:2109) android.widget.LinearLayout cannot be cast to android.widget.TextView at this line: final String text = (String) ((TextView)view).getText(); Any idea how to get the text in this issue? the adapter looks like this: public View getView(int position, View convertView, ViewGroup parent) { LayoutInflater inflater = (LayoutInflater) context .getSystemService(Context.LAYOUT_INFLATER_SERVICE); View rowView = inflater.inflate(R.layout.shortmenue, parent, false); TextView textView = (TextView) rowView.findViewById(R.id.contents); textView.setText(values[position]); // Change icon
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