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Alex Rivera
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The following are two arrays: import difflib import scipy import numpy a1=numpy.array(['198.129.254.73','134.55.221.58','134.55.219.121','134.55.41.41','198.124.252.101'], dtype='|S15') b1=numpy.array(['198.124.252.102','134.55.41.41','134.55.219.121','134.55.219.137','134.55.220.45', '198.124.252.130'],dtype='|S15') difflib.get_close_matches(a1[-1],b1,2) output: ['198.124.252.130', '198.124.252.102'] shouldnt '198.124.252.102' be the closest match for '198.124.252.101' ? I looked at the documentation where they have specified about some floating type weights but no information on algorithm use. I am in need to find if the absolute difference between the last two octet is 1 (provided the first three octets are same). So I am finding the closest string first and then checking that closest string for the above condition. Is there any other function or way to achieve this? Also how does get_close_matches() behave? ipaddr doesnt seem to have such a manipulation for ips.
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