Extract pattern from a string

Asked 2012-07-18T01:21:45.907

In bash script, what is the easy way to extract a text pattern from a string?

For example, I want to extract X followed by 2 digits in the end of the string?

bash

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1 Answer

$ foo="abcX23"
$ echo "$(echo "$foo" | sed 's/.*\(X[0-9][0-9]\)$/\1/')"
X23

if [[ "$foo" =~ X[0-9][0-9]$ ]]; then
  echo "${foo:$((${#foo}-3))}"
fi

answered 2012-07-18T01:28:03.300