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How do I properly 'printf' an integer and a string in C?

Asked 2012-07-31T02:46:31.027
32

I have the following code:

char *s1, *s2;
char str[10];

printf("Type a string: ");
scanf("%s", str);

s1 = &str[0];
s2 = &str[2];

printf("%s\n", s1);
printf("%s\n", s2);

When I run the code, and enter the input "A 1" as follow:

Type a string: A 1

I got the following result:

A
�<�

I'm trying to read the first character as a string and the third character as an integer, and then print those out on the screen. The first character always works, but the screen would just display random stuffs after that.... How should I fix it?

c string input printf
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1 Answer

45

You're on the right track. Here's a corrected version:

char str[10];
int n;

printf("type a string: ");
scanf("%s %d", str, &n);

printf("%s\n", str);
printf("%d\n", n);

Let's talk through the changes:

  1. allocate an int (n) to store your number in
  2. tell scanf to read in first a string and then a number (%d means number, as you already knew from your printf

That's pretty much all there is to it. Your code is a little bit dangerous, still, because any user input that's longer than 9 characters will overflow str and start trampling your stack.

answered 2012-07-31T02:50:08.563

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