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Alex Rivera
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a* means zero or more instances of: a right? so why does $_ = "a"; s/a*/e/g produce: ee Possible answer: it's replacing the string: "a" with: "e" and it's replacing the empty string: "" with: "e" as well. Or it's replacing the mere absence of a letter: a with a letter: e or it's replacing "zero occurrences" of: a with an: e Ok then, but: $_ = "b"; s/a*/e/g produces: ebe It seems to be replacing the empty string to the left of: b and also the empty string to the right of: b OK. But then why doesn't it do that for: " a " ? Why doesn't it replace the empty string to the left of: a and also the empty string to the right of: a and also the letter: a itself to get: eee ? There are just as many zero occurrences of: a on the left side as the right side!
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