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pymongo throws me an error when trying to query and element from tags db.users.find({"pseudo":"alucaard"}).distinct("produit_up") Out[1]: [{u'abus': 0, u'avctype': u'image/jpeg', u'date': u'2012-09-15', u'description': u'le fameux portable solide', u'id': u'alucaard134766932677', u'namep': u'nokia 3310', u'nombre': 1, u'orientation': u'portrait', u'photo': ObjectId('5053cd4e3a5f3a0990da8a61'), u'prix': 1000, u'tags': [u'solide', u'le', u'fameux', u'portable'], u'vendu': False}] list(db.users.find({"solide":{"$in":{"document_up.tags"}}})) Traceback (most recent call last): File "C:\Python27\lib\site-packages\IPython\core\interactiveshell.py", line 2746, in run_code exec code_obj in self.user_global_ns, self.user_ns File "<ipython-input-1-8dff98261d7a>", line 1, in <module> list(db.users.find({"solide":{"$in":{"document_up.tags"}}})) File "C:\Python27\lib\site-packages\pymongo\cursor.py", line 778, in next if len(self.__data) or self._refresh(): File "C:\Python27\lib\site-packages\pymongo\cursor.py", line 729, in _refresh self.__uuid_subtype)) InvalidDocument: Cannot encode object: set(['document_up.tags']) NB: just a trick for the pymongo users, if your users have a limited size in text, just convert it using a set, the convert the set to a list: for example : phrase = "hi you, how are you, am i using this" first step: remove comma or dots to avoid regular expression searchs. second, use phrase.split() to split words. add this to a set to avoid duplicate words. convert the set to a list it will be a good idea to make a dictionnary that containing some words that will be removed from the list, like "how", "you", "me", ... but it will make a lot of calculation. hope this idea will help.

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