C++11: In what order are lambda captures destructed?

Let's say I have two local smart pointers, foo and bar.

shared_ptr<Foo> foo = ...
shared_ptr<Bar> bar = ...

These smart pointers are wrappers around resources that for some reason must be destructed in the order foo, then bar.

Now I want to create a lambda that uses foo and bar, but outlives the scope containing them. So I'd capture them by value, like this:

auto lambda = [foo, bar]() { ... };

This creates copies of foo and bar within the function object. When the function object is destructed, these copies will be destructed, as well, but I care about the order in which this happens. So my question is:

When a lambda object is destructed, in what order are its by-value captures destructed? And how can I (hopefully) influence this order?