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I have a rather basic C++ question: Consider a function that takes some input parameters and creates a std::string from those parameters like the one below: std::string constructString( int some_parameter ) { std::stringstream ss; // Construct a string (arbitrarily complex) ss << "Some parameter is " << some_parameter << " right now"; return ss.str(); //Am I not returning a temporary object here? } I understand that the stringstream object will go out of scope when the function returns, but doesn't that invalidate the constructed string as well? What would happen if I changed the return type to const char * and returned ss.str().c_str() instead? Code like the above seems to work, but I suspect that's just because the memory containing the 'temporary' object has not yet been overwritten with something else when I use it? I have to admit, I'm rather confused in such situations in general; I'd appreciate it if someone could explain this whole "temporary objects" thing to me (or just point me in the right direction).

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