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is it possible to directly select a column of all nested lists within a list? My list is created using aggregate() with table(): AgN=aggregate(data,by=list(d$date),FUN=table,useNA="no") AgN$x looks like: $`0` 1 2 3 9 11 0.447204969 0.438509317 0.096894410 0.009937888 0.007453416 $`1` 1 2 4 8 11 0.489974937 0.389724311 0.102756892 0.006265664 0.011278195 … $n I want to get a vector of a specific column of each table, e.g. a vector containing the values of all columns named "1". I am still a R beginner, but even after searching and trying for a long time I found no nice solution. If I want to get the field of a list, I can simply index it with brackets, e.g. [i,j]. Online I found some examples for matrices, so I tried to do the same, at first only selecting one nested list’s column with AgN$x[1][1] , but that is still selecting a whole list: $ 0 1 2 3 8 11 0.447204969 0.438509317 0.096894410 0.009937888 0.007453416 My next try was AgN$x[[1]][1] , and it was working: 1 0.447205 So I tried to to the same to select the value of each first column of all nested lists: AgN$x[[1:length(AgN$x]][1] Recursive indexing failed at level 2 Appearently the problem is that it is forbidden to select a range if you use a double brackets. My last try was to use an for loop: cduR=NULL for (i in 1:length(AgN$x)){ t=AgN$x[[i]] cduR=c(cduR,as.vector(t["1"])) } Finally, so far that seems to working. But that way I had to build a loop each time when I want to select columns. Is there no

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