I know that || and && are defined as short-circuit operators in C#, and such behaviour is guaranteed by the language specification, but do |= and &= short-circuit too?

For example:

private bool IsEven(int n)
{
    return n % 2 == 0;
}

private void Main()
{
    var numbers = new int[] { 2, 4, 6, 8, 9, 10, 14, 16, 17, 18, 20 };

    bool allEven = true;
    bool anyOdd = false;

    for (int i = 0; i < numbers.Length; i++)
    {
        allEven &= IsEven(numbers[i]);
        anyOdd |= !IsEven(numbers[i]);
    }
}

When the 9 entry is hit, allEven becomes false, meaning that all subsequent entries are irrelevant - the value of allEven is guaranteed to be false for all future calls to that expression. The same goes for anyOdd, which is set to true when it sees 9, and will remain true for all subsequent calls to that expression.

So, do &= and |= shortcut, or is IsEven guaranteed to be called on every iteration? Is there any defined behaviour in the language specification for this case? Are there any corner-cases where such short circuiting would be problematic?

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