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Alex Rivera
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I was looking at the P/Invoke declaration of RegOpenKeyEx when I noticed this comment on the page: Changed IntPtr to UIntPtr : When invoking with IntPtr for the handles, you will run into an Overflow. UIntPtr is the right choice if you wish this to work correctly on 32 and 64 bit platforms. This doesn't make much sense to me: both IntPtr and UIntPtr are supposed to represent pointers so their size should match the bitness of the OS - either 32 bits or 64 bits. Since these are not numbers but pointers, their signed numeric values shouldn't matter, only the bits that represent the address they point to. I cannot think of any reason why there would be a difference between these two but this comment made me uncertain. Is there a specific reason to use UIntPtr instead of IntPtr ? According to the documentation : The IntPtr type is CLS-compliant, while the UIntPtr type is not. Only the IntPtr type is used in the common language runtime. The UIntPtr type is provided mostly to maintain architectural symmetry with the IntPtr type. This, of course, implies that there's no difference (as long as someone doesn't try to convert the values to integers). So is the above comment from pinvoke.net incorrect? Edit : After reading MarkH's answer , I did a bit of checking and found out that .NET applications are not large address aware and can only handle a 2GB virtual address space when compiled in 32-bit mode. (One can u
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