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Alex Rivera
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while browsing one of my old questions on constexpr I stumbled onto a very(IMHO) important comment. Basically it boils down to : (this is legal C++11 :( ) constexpr double f(bool b) { return b? 42:42/(rand()+1); // how pure is rand ;) } My question is what is the reason this is allowed by the standard. Since Im a big fan of referential transparency I hope they have a good reason :) and I would like to know it. BTW there is related Q but most of the A even dont mention pure thing, or when they do they dont specify the reasoning why std allows this. Relation between constexpr and pure functions
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