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MongoDB: Find the minimum element in array and delete it

Asked 2012-11-11T20:15:40.270
13

I have a documents in MongoDB, one of them looks like this:

{
"_id" : 100,
"name" : "Something",
"items" : [
    {
        "item" : 47,
        "color" : "red"
    },
    {
        "item" : 44,
        "color" : "green"
    },
    {
        "item" : 39,
        "color" : "blue"
    }
]
}

In every document I need to find the minimum item and delete it. So it should be like this:

{
"_id" : 100,
"name" : "Something",
"items" : [
    {
        "item" : 47,
        "color" : "red"
    },
    {
        "item" : 44,
        "color" : "green"
    }
]
}

It looks like findAndModify function should be used here but I can't go any further.

How to find the minimum element in array and delete it?

I'm using MongoDB and Pymongo driver.

python mongodb pymongo
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1 Answer

18

If you are not restricted to having the query be in one single step, you could try:

step 1) use the aggregate function with the $unwind and $group operators to find the minimum item for each document

myresults = db.megas.aggregate( [ { "$unwind": "$items" },  
    {"$group": { '_id':'$_id' , 'minitem': {'$min': "$items.item" } } } ] )

step 2) the loop through the results and $pull the element from the array

for result in myresults['result']:
    db.megas.update( { '_id': result['_id'] }, 
        { '$pull': { 'items': { 'item': result['minitem'] } } } )
answered 2012-11-12T17:58:23.847

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