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Alex Rivera
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I wrote the following code: #include <iostream> #include <iomanip> #include <stdint.h> using namespace std; int main() { uint8_t c; cin >> hex >> c; cout << dec << c; return 0; } But when I input c —hex for 12—the output is also c . I was expecting 12. Later I learned that: uint8_t is usually a typedef for unsigned char . So it's actually reading c as ASCII 0x63. Is there a 1 byte integer which behaves as an integer while doing I/O and not as char?
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