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#include <stdio.h> volatile int i; int main() { int c; for (i = 0; i < 3; i++) { c = i &&& i; printf("%d\n", c); } return 0; } The output of the above program compiled using gcc is 0 1 1 With the -Wall or -Waddress option, gcc issues a warning: warning: the address of ‘i’ will always evaluate as ‘true’ [-Waddress] How is c being evaluated in the above program?
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