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Consider the following header and source files: // main.cpp #include "myClass.h" int main() { MyClass m; m.foo<double>(); m.foo<float>(); } // myClass.h #pragma once #include <iostream> using namespace std; class MyClass { public: template <typename T> void foo() { cout << "Template function<T> called" << endl; } template <> void foo<int>() { cout << "Template function<int> called" << endl; } template <> void foo<float>(); }; // myClass.cpp #include "myClass.h" template <> void MyClass::foo<float>() { cout << "Template function<float> called" << endl; } I get a linking error wrt the foo<float> specialization. If I place the definition of the specialization in the header file, then everything works as expected. I figured that the reason may be that the method is not explicitly instantiated (although full specialization of template class does not need an explicit instantiation for proper linking). If I try to explicitly instantiate the method, I get this error: error C3416: 'MyClass::foo' : an explicit specialization may not be explicitly instantiated So the questions are: Is there any way to define the specialization in the cpp file and link properly? If not, why not? I can explicitly instantiate template methods that are not specialized just fine. Why not the same for full specializations?

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