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Alex Rivera
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In Scala, I have a regular expression pattern match like this: val Regex = """(\d{4})/(\d{2})/(\d{2})""".r val Regex(year, month, day) = "2013/01/06" The result is: year: String = 2013 month: String = 01 day: String = 06 How can I accomplish a similar result in Haskell? In other words, can I match a regular expression containing groups and assign the groups to identifiers?
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