How do I use variadic perfect forwarding into a lambda?

I have a working function template that calls a lambda.

I would like to generalize this function template to take variadic arguments and forward them perfectly into the lambda, but I am having trouble getting this code to compile.

I am using gcc 4.7.2.

UPDATE

Using R. Martinho Fernandes's suggestion, I looked up the error in bugzilla - it does look like a bug that's been around for a while. If anyone knows of a workaround (I'm digging around for one now), please post an answer - ty.

ERRORS

junk.cpp: In lambda function:
junk.cpp:32:68: error: parameter packs not expanded with ‘...’:
junk.cpp:32:68: note:         ‘args’
junk.cpp: In instantiation of ‘std::pair<std::basic_string<char>, typename T::Lambda> MP(const string&, M, Args&& ...) [with T = Integer; M = int (Integer::*)()const; Args = {}; typename T::Lambda = std::function<std::function<int()>(const Integer&)>; std::string = std::basic_string<char>]’:
junk.cpp:47:42:   required from here
junk.cpp:34:2: error: using invalid field ‘MP(const string&, M, Args&& ...)::<lambda(const T&)>::__args’
make: *** [junk] Error 1

CODE

#include <functional>
#include <iostream>
#include <map>

struct Integer
{
    typedef std::function<int()>                            Function;
    typedef std::function<Function( Integer const& inst )>  Lambda;

    virtual int getInt() const = 0;
};

struct IntImpl : public Integer
{
    virtual int getInt() const { return 42; }
};

typedef std::function<int()>                               IntFunction;
typedef std::function<IntFunction( Integer const& inst )>  IntLambda;

#define WONT_COMPILE

template<typename T,typename M,typename... Args>
std::pair<std::string