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I'm trying to convert a lat/long point into a 2d point so that I can display it on an image of the world-which is a mercator projection. I've seen various ways of doing this and a few questions on stack overflow-I've tried out the different code snippets and although I get the correct longitude to pixel, the latitude is always off-seems to be getting more reasonable though. I need the formula to take into account the image size, width etc. I've tried this piece of code: double minLat = -85.05112878; double minLong = -180; double maxLat = 85.05112878; double maxLong = 180; // Map image size (in points) double mapHeight = 768.0; double mapWidth = 991.0; // Determine the map scale (points per degree) double xScale = mapWidth/ (maxLong - minLong); double yScale = mapHeight / (maxLat - minLat); // position of map image for point double x = (lon - minLong) * xScale; double y = - (lat + minLat) * yScale; System.out.println("final coords: " + x + " " + y); The latitude seems to be off by about 30px in the example I'm trying. Any help or advice? Update Based on this question: Lat/lon to xy I've tried to use the code provided but I'm still having some problems with latitude conversion, longitude is fine. int mapWidth = 991; int mapHeight = 768; double mapLonLeft = -180; double mapLonRight = 180; double mapLonDelta = mapLonRight - mapLonLeft; double mapLatBottom = -85.05112878; double mapLatBottomDegree = mapLatBottom * Math.PI / 180; double worldMapWidth = ((mapWidth / mapLonDelta) * 360) / (2 * Math.PI); double mapOffsetY = (worldMapWidth / 2 * Math.log((1 + Math.sin(mapLatBottomDegree)) / (1 - Math.sin(mapLatBottomDegree)))); double x = (lon - mapLonLeft) * (mapWidth / mapLonDelta); double y = 0.1; if (lat

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