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I am trying to print floats. Although variadic functions does not work with floats so they are promoted to double. I can manage to get rid of the warning by casting it to a double. While printing the results on some powerpc architecture, it gives incorrect value if printed with %f. Why ? Test Code: #include <stdio.h> #define _echo_size(X) \ printf ("Sizeof "#X" %u\n", sizeof(X)) int main (void) { float x; long usec = 7L; _echo_size(float); _echo_size(double); _echo_size(short); _echo_size(int); _echo_size(long); _echo_size(long long); x = ((float) usec) / 2; printf("Expected: 3.5 Got: %1.1f\n", (double) x); printf("Expected: 3.5 Got: %1d.%.1d\n", (int)x, (int)((x-(int)x)*10)); return 0; } X86 system result: Sizeof float 4 Sizeof double 8 Sizeof short 2 Sizeof int 4 Sizeof long 8 Sizeof long long 8 Expected: 3.5 Got: 3.5 Expected: 3.5 Got: 3.5 ppc system result: Sizeof float 4 Sizeof double 8 Sizeof short 2 Sizeof int 4 Sizeof long 4 Sizeof long long 8 Expected: 3.5 Got: 0.0 <--- Why this ? Expected: 3.5 Got: 3.5 Is it a bug in the tool-chain ? otherwise what is the elegant way to print floats ?

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