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I read that when in a catch block, I can rethrow the current exception using "throw;" or "throw ex;". From: http://msdn.microsoft.com/en-us/library/ms182363%28VS.80%29.aspx "To keep the original stack trace information with the exception, use the throw statement without specifying the exception." But when I try this with try{ try{ try{ throw new Exception("test"); // 13 }catch (Exception ex1){ Console.WriteLine(ex1.ToString()); throw; // 16 } }catch (Exception ex2){ Console.WriteLine(ex2.ToString()); // expected same stack trace throw ex2; // 20 } }catch (Exception ex3){ Console.WriteLine(ex3.ToString()); } I get three different stacks. I was expecting the first and second trace to be the same. What am I doing wrong? (or understanding wrong?) System.Exception: test at ConsoleApplication1.Program.Main(String[] args) in c:\Program.cs:line 13 System.Exception: test at ConsoleApplication1.Program.Main(String[] args) in c:\Program.cs:line 16 System.Exception: test at ConsoleApplication1.Program.Main(String[] args) in c:\Program.cs:line 20

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