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I typically use the following code in JavaScript to split a string by whitespace. "The quick brown fox jumps over the lazy dog.".split(/\s+/); // ["The", "quick", "brown", "fox", "jumps", "over", "the", "lazy", "dog."] This of course works even when there are multiple whitespace characters between words. "The quick brown fox jumps over the lazy dog.".split(/\s+/); // ["The", "quick", "brown", "fox", "jumps", "over", "the", "lazy", "dog."] The problem is when I have a string that has leading or trailing whitespace in which case the resulting array of strings will include an empty character at the beginning and/or end of the array. " The quick brown fox jumps over the lazy dog. ".split(/\s+/); // ["", "The", "quick", "brown", "fox", "jumps", "over", "the", "lazy", "dog.", ""] It's a trivial task to eliminate such empty characters, but I'd rather take care of this within the regular expression if that's at all possible. Does anybody know what regular expression I could use to accomplish this goal?

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