14
You can use setjmp and logjmp functions to do this as shown in this C FAQ
For those who are curious to why someone have a question like this, this is one of the frequently asked questions in India for recruiting fresh grads.
write all possible output to a string first, and null terminate it where the output should stop.
this is a rather dirty solution, but given the limitations, all I can think of,
except for using assembler, off course.
char a[]="1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n11\n12\n13\n14\n15\n16\n17\n"/*...*/;
main(n,v)char**v;{n=atoi(v[1]);
#define c(x)(n>x?n-x:0)
a[n+c(1)+c(9)+c(99)+c(999)+c(9999)+c(99999)+c(999999)+c(9999999)/*+...*/]=0;
puts(a);}
Given that MAX_INT==2147483647 on popular architectures, we only need to go up to +c(999999999). Typing out that initial string might take a while, though...
#include "stdio.h"
#include "stdlib.h"
#include "signal.h"
int g_num;
int iterator;
void signal_print()
{
if(iterator>g_num-1)
exit(0);
printf("%d\n",++iterator);
}
void myprintf(int n)
{
g_num=n;
int *p=NULL;
int x= *(p); // the instruction is reexecuted after handling the signal
}
int main()
{
signal(SIGSEGV,signal_print);
int n;
scanf("%d",&n);
myprintf(n);
return 0;
}
/// <summary>
/// Print one to Hundred without using any loop/condition.
/// </summary>
int count = 100;
public void PrintOneToHundred()
{
try
{
int[] hey = new int[count];
Console.WriteLine(hey.Length);
count--;
PrintOneToHundred();
}
catch
{
Console.WriteLine("Done Printing");
}
}