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I'm trying to generate a simple JSON response working. Right now I get 406 Not Acceptable error. Tomcat says "The resource identified by this request is only capable of generating responses with characteristics not acceptable according to the request "accept" headers." even though my Accept headers are Accept:text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8 In tomcat/lib I have all Tomcat jars, Spring jars and jackson-all-1.9.0.jar. I'm using Spring 3.2.2 with Tomcat 7. I'm aware that this issue has been discussed many times, but none of solutions is working for me. web.xml <web-app id="WebApp_ID" version="2.4" xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd"> <display-name>Spring Web MVC Application</display-name> <servlet> <servlet-name>dispatcher</servlet-name> <servlet-class> org.springframework.web.servlet.DispatcherServlet </servlet-class> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>dispatcher</servlet-name> <url-pattern>*.htm</url-pattern> </servlet-mapping> </web-app> dispatcher-servlet.xml <beans xmlns="http://www.springframework.org/schema/beans" xmlns:context="http://www.springframework.org/schema/context" xmlns:mvc="http://www.springframework.org/schema/mvc" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd http://www.springframework.org/schema/context

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