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Label width in tkinter

Asked 2013-05-03T16:10:22.940
11

I'm writing an app with tkinter and I am trying to put several labels in a frame... Unfortunately,

windowTitle=Label(... width=100)

and

windowFrame=Frame(... width=100)

are very different widths...

So far, I use this code:

windowFrame=Frame(root,borderwidth=3,relief=SOLID,width=xres/2,height=yres/2)
windowFrame.place(x=xres/2-160,y=yres/2-80)
windowTitle=Label(windowFrame,background="#ffa0a0",text=title)
windowTitle.place(x=0,y=0)
windowContent=Label(windowFrame,text=content,justify="left")
windowContent.place(x=8,y=32)

...

#xres is screen width
#yres is screen height

For some reason, setting label width doesn't set width correctly, or doesn't use pixels as measurement units... So, is there a way to place windowTitle widget in such way that it adapts to the lenght of the frame, or to set label width in pixels?

python tkinter width label frame
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1 Answer

15

height and width define the size of the label in text units when it contains text. Follow @Elchonon Edelson's advice and set size of frame + one small trick:

from tkinter import *
root = Tk()

def make_label(master, x, y, h, w, *args, **kwargs):
    f = Frame(master, height=h, width=w)
    f.pack_propagate(0) # don't shrink
    f.place(x=x, y=y)
    label = Label(f, *args, **kwargs)
    label.pack(fill=BOTH, expand=1)
    return label

make_label(root, 10, 10, 10, 40, text='xxx', background='red')
make_label(root, 30, 40, 10, 30, text='xxx', background='blue')

root.mainloop()
answered 2013-05-03T16:42:33.347

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