KnowledgeHub
Questions
Tags
Users
Search
Alex Rivera
|
Logout
Edit Question
Title
Body
When I click of a Button I'm using the following code for a function for a Dialog: function Confirmation(msg1){ if ($('#exportSales').length == 0) { $(document.body).append('<div id="exportSales">'+msg1+'</div>'); } else { $('#exportSales').html(msg1); } $("#exportSales").dialog({ autoOpen: false, show: "blind", hide: "explode", height: 450, width: 1000, modal: true }); $( "#exportSales" ).dialog("open"); } However, when I inspect this in FireBug it is showing this error in the console: TypeError: $(...).dialog is not a function [Break On This Error] modal: true EDIT : There is another dialog also in the document that runs fine. when I comment out that one then this dialog then starts working. How do I change my code so they can work together in the same page?
Tags (comma-separated)
Save Edits
Cancel