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I'm rather new to python, and I want to make sure I'm doing this correctly. I'd like to have an exception class: class UnknownCommandReceived(Exception): def __init__(self, value): self.value = value def __str__(self): return repr(self.value) I will raise the exception at the end of this function if no regexes match: def cmdType(self): match = re.match(r'(<[ \w]+>),\s*(\d+)?,?\s*(\d+)?', cmd, re.IGNORECASE) if match: cmd_type = 'int_tool' return cmd_type, match match = re.match(r'LCD\(([^\)]*)\)?_?(RED|YELLOW|GREEN|TEAL|BLUE|VIOLET|OFF|ON|SELECT|LEFT|DOWN|RIGHT)?', cmd, re.IGNORECASE) if match: cmd_type = 'lcd' return cmd_type, match match = re.match(r'buffer(_read|_num|_line)(\((\w)\))?', cmd, re.IGNORECASE) if match: cmd_type = 'buffer' return cmd_type, match # ... More regex matches ... raise UnknownCommandReceived( "cmdType received an unknown command" ) # unecessary return? return 'None', None My question is--if the exception is always raised, then do I not need a return statement at the end of the function? My apologies.. its a very basic question. My understanding is that an exception once an exception is raised, execution will never return to that point of the code (unless its a loop, or a function that is called again). It will go straight to the catch and continue from there?

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