Can std::function be move-constructed from rvalue reference to a temporary functor object?

I have an untemplated functor object that I'm trying to store as a std::function inside another object. This object is really heavyweight, so it's marked as uncopyable, but it does have a move constructor. However, trying to construct a std::function, or assign it, from a temporary constructor fails.

Here is a minimal example to provoke the error.

// pretend this is a really heavyweight functor that can't be copied.
struct ExampleTest
{
    int x;
    int operator()(void) const {return x*2;}
    ExampleTest(  ) :x(0){}
    ExampleTest( int a ) :x(a){}

    // allow move
    ExampleTest( ExampleTest &&other ) :x(other.x) {};

private: // disallow copy, assignment
    ExampleTest( const ExampleTest &other );
    void operator=( const ExampleTest &other );
};

// this sometimes stores really big functors and other times stores tiny lambdas.
struct ExampleContainer
{
    ExampleContainer( int );
    std::function<int(void)> funct;
};

/******** ERROR:
 Compiler error: 'ExampleTest::ExampleTest' : cannot access private member 
 declared in class 'ExampleTest'
******************/
ExampleContainer::ExampleContainer( int x )
    : funct( ExampleTest( x ) ) 
{}

/******** ERROR:
 Compiler error: 'ExampleTest::ExampleTest' : cannot access private member 
 declared in class 'ExampleTest'
******************/
int SetExample( ExampleContainer *container )
{
    container->funct = ExampleTest();
    return container->funct();
}

In an even simpler construction, where I'm just making a local function, I also get the error:

int ContrivedExample(  )
{
    // extra parens to sidestep most vexing parse 
    std::function<int()> zug( (ExampleTest()) );
    /*** ERROR: 'ExampleTest::ExampleTest' : cannot access private member
         declared in class 'ExampleTest' */
    int troz = zug(  ) ;
    return troz;
}

So far as I can tell, in all of these cases, a tempo