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Alex Rivera
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I heard that you could right-shift a number by .5 instead of using Math.floor(). I decided to check its limits to make sure that it was a suitable replacement, so I checked the following values and got the following results in Google Chrome: 2.5 >> .5 == 2; 2.9999 >> .5 == 2; 2.999999999999999 >> .5 == 2; // 15 9s 2.9999999999999999 >> .5 == 3; // 16 9s After some fiddling, I found out that the highest possible value of two which, when right-shifted by .5, would yield 2 is 2.9999999999999997779553950749686919152736663818359374999999¯ (with the 9 repeating) in Chrome and Firefox. The number is 2.9999999999999997779¯ in IE. My question is: what is the significance of the number .0000000000000007779553950749686919152736663818359374? It's a very strange number and it really piqued my curiosity. I've been trying to find an answer or at least some kind of pattern, but I think my problem lies in the fact that I really don't understand the bitwise operation. I understand the idea in principle, but shifting a bit sequence by .5 doesn't make any sense at all to me. Any help is appreciated. For the record, the weird digit sequence changes with 2^x. The highest possible values of the following numbers that still truncate properly: for 0: 0.9999999999999999444888487687421729788184165954589843749¯ for 1: 1.9999999999999999888977697537484345957636833190917968749¯ for 2-3: x+.99999999999999977795539507496869191527366638183593749¯ for 4-7: x+.9999999999999995559107901499373838305473327636718749¯ for 8-15: x+.999999999999999111821580299874767661094665527343749¯ ...and so forth
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