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tl;dr: Is there a non-short circuit logical AND in C++ (similar to &&)? I've got 2 functions that I want to call, and use the return values to figure out the return value of a 3rd composite function. The issue is that I always want both functions to evaluate (as they output log information about the state of the system) IE: bool Func1(int x, int y){ if( x > y){ cout << "ERROR- X > Y" << endl; } } bool Func2(int z, int q){ if( q * 3 < z){ cout << "ERROR- Q < Z/3" << endl; } } bool Func3(int x, int y, int z, int q){ return ( Func1(x, y) && Func2(z, q) ); } Of course, the conditionals aren't quite that simple in the functions, and yes, I realize that I could use temporary variables to store the returns of the two functions and then do the "short-circuit" logic on the temporary variables, but I was wondering if there was an "elegant" language solution to keep the one-line return in Func3 while still getting the logging messages from both functions. Summary of responses: The "bitwise" operators | and & can be used to get the effect, but only if the return type is bool. I found no mention of this in the ANSI C++ spec. From what I can tell, this works because the "bool" is converted to an int (true = 1, false = 0), and then the bitwise operator is used, then it is converted back to a bool. The Operators " + " and " * " can also be used. This is not mentioned in the ANSI C++ Spec, but probably works because of the same reason as above. " + " give "or" because true is converted to 1, and then anything other than 0 is converted back to true. " * " works for "and" because 1 (true) * 0 (false) == 0(false) and 1(true) * 1(true) == 1(true) Both of these seem to rely on implicit type conversion to integer and then back to bool. Both of these will likely mess up whomeve

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