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The stream comes from an html form via ajax var jqXHR = data.submit(); public static GetWordPlainText(Stream readStream,string filePath) { WordprocessingDocument.Open(readStream, readStream.CanRead); } [HttpPost] public ActionResult FileUpload() { var MyFile = Request.Files[0]; if (Request.Files.Count > 0 && MyFile != null) { GetWordPlainText(Request.InputStream); } } I get this error: Cannot open package because FileMode or FileAccess value is not valid for the stream. I google Cannot open package because FileMode or FileAccess value is not valid for the stream but can't find anything useful. Any ideas? PS: Initially I simplified the code to be posted here to much. Added the if statement so that it would erase the concern by Sten Petrov. I hope Request.File.count>0 does address his concern... I still have the same problem... UPDATE As a work around I followed the advise below and save the file to a directory then I use openxml to read it from the directory var MyFile = Request.Files[0]; var path = Path.Combine(Server.MapPath("~/App_Data/temp"), MyFile.FileName); using (MemoryStream ms = new MemoryStream()) { //if file exist plz!!!! TODO Request.Files[0].InputStream.CopyTo(ms); System.IO.File.WriteAllBytes(path, ms.ToArray()); } then WordprocessingDocument.Open has a implementation for filepath so WordprocessingDocument.Open(path); hope you get the idea of what I did for future people that have problems.

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