KnowledgeHub
Questions
Tags
Users
Search
Alex Rivera
|
Logout
Edit Question
Title
Body
How can I use two cursors in the same routine? If I remove the second cursor declaration and fetch loop everthing works fine. The routine is used for adding a friend in my webapp. It takes the id of the current user and the email of the friend we want to add as a friend, then it checks if the email has a corresponding user id and if no friend relation exists it will create one. Any other routine solution than this one would be great as well. DROP PROCEDURE IF EXISTS addNewFriend; DELIMITER // CREATE PROCEDURE addNewFriend(IN inUserId INT UNSIGNED, IN inFriendEmail VARCHAR(80)) BEGIN DECLARE tempFriendId INT UNSIGNED DEFAULT 0; DECLARE tempId INT UNSIGNED DEFAULT 0; DECLARE done INT DEFAULT 0; DECLARE cur CURSOR FOR SELECT id FROM users WHERE email = inFriendEmail; DECLARE CONTINUE HANDLER FOR NOT FOUND SET done = 1; OPEN cur; REPEAT FETCH cur INTO tempFriendId; UNTIL done = 1 END REPEAT; CLOSE cur; DECLARE cur CURSOR FOR SELECT user_id FROM users_friends WHERE user_id = tempFriendId OR friend_id = tempFriendId; DECLARE CONTINUE HANDLER FOR NOT FOUND SET done = 1; OPEN cur; REPEAT FETCH cur INTO tempId; UNTIL done = 1 END REPEAT; CLOSE cur; IF tempFriendId != 0 AND tempId != 0 THEN INSERT INTO users_friends (user_id, friend_id) VALUES(inUserId, tempFriendId); END IF; SELECT tempFriendId as friendId; END // DELIMITER ;
Tags (comma-separated)
Save Edits
Cancel