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I'm doing some simple HTTP authentication and am getting a java.lang.IllegalArgumentException: Illegal character(s) in message header value: Basic OGU0ZTc5ODBk(...trimmed from 76 chars...) (...more password data...) which I think is due to me having a really long username and password and the encoder wraps it with a \n at 76 chars. Is there any way I can get around this? The URL only supports HTTP Basic Auth. Here is my code: private class UserPassAuthenticator extends Authenticator { String user; String pass; public UserPassAuthenticator(String user, String pass) { this.user = user; this.pass = pass; } // This method is called when a password-protected URL is accessed protected PasswordAuthentication getPasswordAuthentication() { return new PasswordAuthentication(user, pass.toCharArray()); } } private String fetch(StoreAccount account, String path) throws IOException { Authenticator.setDefault(new UserPassAuthenticator(account.getCredentials().getLogin(), account.getCredentials().getPassword())); URL url = new URL("https", account.getStoreUrl().replace("http://", ""), path); System.out.println(url); URLConnection urlConn = url.openConnection(); Object o = urlConn.getContent(); if (!(o instanceof String)) throw new IOException("Wrong Content-Type on " + url.toString()); // Remove the authenticator back to the default Authenticator.setDefault(null); return (String) o; }

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