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Suppose I want to pass a temporary object into a function. Is there a way to do that in 1 line of code vs. 2, with a struct? With a class, I can do: class_func(TestClass(5, 7)); given: class TestClass { private: int a; short b; public: TestClass(int a_a, short a_b) : a(a_a), b(a_b) { } int A() const { return a; } short B() const { return b; } }; void class_func(const TestClass & a_class) { printf("%d %d\n", a_class.A(), a_class.B()); } Now, how do I do that with a struct? The closest I've got is: test_struct new_struct = { 5, 7 }; struct_func(new_struct); given: struct test_struct { int a; short b; }; void struct_func(const test_struct & a_struct) { printf("%d %d\n", a_struct.a, a_struct.b); } The object is more simple, but I wonder if there's a way to do the struct member initialization right in line with the function call, without giving the struct a constructor. (I don't want a constructor. The whole reason I'm using a struct is to avoid the boilerplate get/set class conventions in this isolated case.)

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