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Alex Rivera
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This simple test, of course, works as expected: scala> var b = 2 b: Int = 2 scala> b += 1 scala> b res3: Int = 3 Now I bring this into scope: class A(var x: Int) { def +=(y:Int) { this.x += y } } implicit def int2A(i:Int) : A = new A(i) I'm defining a new class and a += operation on it, and a convenient implicit conversion for those times when I want to add an Int to A's Int value. I never expected this would affect the way my regular Int operations behave, when the "A" class is not at all part of the expression. But it does: scala> var b:Int = 0 b: Int = 0 scala> b += 1 scala> b res29: Int = 0 scala> b += 2 scala> b res31: Int = 0 What seems to be happening here is that the b:Int is implicitly converted to an "A", which is not bound to any variable, and then += is invoked on it, discarding the results. Scala seems to give high precedence the implicit conversion over the natural += behavior (compiler magic, not an actual method) that is already defined to Ints. Common-sense as well as a C++ background tells me implicits should only be invoked as a last resort, when the compilation would otherwise fail. That leads to several questions... Why? Is this a bug? Is it by design? Is there a work-around (other than not using "+=" for my DSL's "+=" operation)? Thanks
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